题解 | #二分查找-II#
二分查找-II
https://www.nowcoder.com/practice/4f470d1d3b734f8aaf2afb014185b395
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # 如果目标值存在返回下标,否则返回 -1 # @param nums int整型一维数组 # @param target int整型 # @return int整型 # import math class Solution: def search(self , nums: List[int], target: int) -> int: # write code here left=0 right=len(nums)-1 while left<=right: mid=int((left+right)/2) if nums[mid]==target: while mid>0 and nums[mid]==nums[mid-1]: mid=mid-1 return mid elif nums[mid]>target: right=mid-1 else: left=mid+1 return -1