题解 | #删除字符串中出现次数最少的字符#

import sys
a = []
b = set()
index = ''

c = {}
for line in sys.stdin:
    a = line.split()
for n in a[0]:
    a.append(n)
    b.add(n)
for index in b:
    count = 0
    for j in range(1,len(a)):
        if index == a[j]:
            count = count +1
    if count in c: 
        if isinstance(c[count], list):
            c[count].append(index)
        else:
            c[count] = [c[count], index]
    else:
        c[count] = index
m = min(c)
a = str(a[0])

for delete in c[m]:
    a = a.replace(delete,"")

print(a)