题解 | #翻转金字塔图案#
翻转金字塔图案
https://www.nowcoder.com/practice/c4775776e4464537bfb6a5ba37c596c6
#include <stdio.h>
int main()
{
int n = 0;
while (scanf("%d", &n) != EOF)
{
for (int i = n; i > 0; i--)
{
for (int j = 0; j < n - i; j++)
{
printf(" ");
}
for (int k = 0; k < i; k++)
{
printf("* ");
}
printf("\n");
}
}
return 0;
}
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