题解 | #牛客每个人最近的登录日期(二)#

牛客每个人最近的登录日期(二)

https://www.nowcoder.com/practice/7cc3c814329546e89e71bb45c805c9ad

select

U.name as "u_n",C.name as "c_n" ,M.date as "date"

from

(select

L.user_id,L.client_id,L.date

from login L

join (

select

user_id,max(date) as date

from login

group by user_id

) as C on C.user_id=L.user_id

and L.date=C.date

) as M

left join user U on U.id=M.user_id

left join client C on C.id=M.client_id

order by U.name asc

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