题解 | #牛客每个人最近的登录日期(二)#
牛客每个人最近的登录日期(二)
https://www.nowcoder.com/practice/7cc3c814329546e89e71bb45c805c9ad
select
U.name as "u_n",C.name as "c_n" ,M.date as "date"
from
(select
L.user_id,L.client_id,L.date
from login L
join (
select
user_id,max(date) as date
from login
group by user_id
) as C on C.user_id=L.user_id
and L.date=C.date
) as M
left join user U on U.id=M.user_id
left join client C on C.id=M.client_id
order by U.name asc