题解 | #用3-8译码器实现全减器#
用3-8译码器实现全减器
https://www.nowcoder.com/practice/4a8f2e5058554cea9c1cb2ac8bdea0a7
`timescale 1ns/1ns
module decoder_38(
input E ,
input A0 ,
input A1 ,
input A2 ,
output reg Y0n ,
output reg Y1n ,
output reg Y2n ,
output reg Y3n ,
output reg Y4n ,
output reg Y5n ,
output reg Y6n ,
output reg Y7n
);
always @(*)begin
if(!E)begin
Y0n = 1'b1;
Y1n = 1'b1;
Y2n = 1'b1;
Y3n = 1'b1;
Y4n = 1'b1;
Y5n = 1'b1;
Y6n = 1'b1;
Y7n = 1'b1;
end
else begin
case({A2,A1,A0})
3'b000 : begin
Y0n = 1'b0; Y1n = 1'b1; Y2n = 1'b1; Y3n = 1'b1;
Y4n = 1'b1; Y5n = 1'b1; Y6n = 1'b1; Y7n = 1'b1;
end
3'b001 : begin
Y0n = 1'b1; Y1n = 1'b0; Y2n = 1'b1; Y3n = 1'b1;
Y4n = 1'b1; Y5n = 1'b1; Y6n = 1'b1; Y7n = 1'b1;
end
3'b010 : begin
Y0n = 1'b1; Y1n = 1'b1; Y2n = 1'b0; Y3n = 1'b1;
Y4n = 1'b1; Y5n = 1'b1; Y6n = 1'b1; Y7n = 1'b1;
end
3'b011 : begin
Y0n = 1'b1; Y1n = 1'b1; Y2n = 1'b1; Y3n = 1'b0;
Y4n = 1'b1; Y5n = 1'b1; Y6n = 1'b1; Y7n = 1'b1;
end
3'b100 : begin
Y0n = 1'b1; Y1n = 1'b1; Y2n = 1'b1; Y3n = 1'b1;
Y4n = 1'b0; Y5n = 1'b1; Y6n = 1'b1; Y7n = 1'b1;
end
3'b101 : begin
Y0n = 1'b1; Y1n = 1'b1; Y2n = 1'b1; Y3n = 1'b1;
Y4n = 1'b1; Y5n = 1'b0; Y6n = 1'b1; Y7n = 1'b1;
end
3'b110 : begin
Y0n = 1'b1; Y1n = 1'b1; Y2n = 1'b1; Y3n = 1'b1;
Y4n = 1'b1; Y5n = 1'b1; Y6n = 1'b0; Y7n = 1'b1;
end
3'b111 : begin
Y0n = 1'b1; Y1n = 1'b1; Y2n = 1'b1; Y3n = 1'b1;
Y4n = 1'b1; Y5n = 1'b1; Y6n = 1'b1; Y7n = 1'b0;
end
default: begin
Y0n = 1'b1; Y1n = 1'b1; Y2n = 1'b1; Y3n = 1'b1;
Y4n = 1'b1; Y5n = 1'b1; Y6n = 1'b1; Y7n = 1'b1;
end
endcase
end
end
endmodule
module decoder1(
input wire A,
input wire B,
input wire Ci,
output wire D,
output wire Co
);
wire [7:0] Y;
assign D = !Y[1] || !Y[2] || !Y[4] || !Y[7];
assign Co = !Y[1] || !Y[4] || !Y[5] || !Y[7];
decoder_38 myDecoder(
.E (1 ),
.A0 (B ),
.A1 (A ),
.A2 (Ci ),
.Y0n(Y[0]),
.Y1n(Y[1]),
.Y2n(Y[2]),
.Y3n(Y[3]),
.Y4n(Y[4]),
.Y5n(Y[5]),
.Y6n(Y[6]),
.Y7n(Y[7])
);
endmodule
将{C_i,A,B}当作{A2,A1,A0},观察可知D为真只有当Y1_n,Y2_n,Y4_n,Y-7n为假的时候成立;
同理,C-o为真只有当Y1_n,Y4_n,Y5_n,Y-7n为假的时候成立;
直接使用 非门 与 逻辑或运算 即可得到真确结果。