题解 | #得分不小于平均分的最低分#

select
    min(score) as min_score_over_avg
from
    exam_record a,
    examination_info b
where
    a.exam_id = b.exam_id
    and b.tag = "SQL"
    and score >= (
        select
            avg(score) as score
        from
            exam_record a,
            examination_info b
        where
            a.exam_id = b.exam_id
            and b.tag = "SQL"
    );