题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
import java.util.*;
public class Solution {
public double Power(double base, int exponent) {
if(base == 0.0) return 0.0;
// 转换
long b = exponent;
if(b < 0) {
b = -b;
base = 1 / base;
}
// 标准的快速幂
double sum = 1.0;
while(b != 0) {
if((b & 1) == 1) {
sum *= base;
}
base *= base;
b >>>= 1;
}
return sum;
}
}
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