题解 | #简单计算器#

#include <stdio.h>
int main() 
{
  double a,b;
  char c;
  scanf("%lf%c%lf",&a,&c,&b);
  switch(c)
  {
    case '+': printf("%.4lf+%.4lf=%.4lf\n",a,b,a+b); break;
    case '-': printf("%.4lf-%.4lf=%.4lf\n",a,b,a-b); break;
    case '*': printf("%.4lf*%.4lf=%.4lf\n",a,b,a*b); break;
    case '/': 
    if(b==0)
    {
        printf("Wrong!Division by zero!\n");
    } 
    else
    {
        printf("%.4lf/%.4lf=%.4lf\n",a,b,a/b);
    }break;
    default :printf("Invalid operation!\n");break;
  }
    return 0;
}