题解 | #有效括号序列#
有效括号序列
https://www.nowcoder.com/practice/37548e94a270412c8b9fb85643c8ccc2
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @return bool布尔型
#
class Solution:
def isValid(self , s: str) -> bool:
# write code here
stack = []
d = {"(":")","[":"]","{":"}"}
for c in s:
if stack and stack[-1] in "([{" and d[stack[-1]] == c:
stack.pop()
else:
stack.append(c)
if stack:
return False
else:
return True

