题解 | #KiKi求质数个数#
KiKi求质数个数
https://www.nowcoder.com/practice/d3a404ee0f8d41f98bf4707035d91086
#include <stdio.h>
int main()
{
int count = 900;
for(int i = 100; i <= 999; i++)
{
for(int j = 2; j < i; j++)
{
if(i % j == 0)
{
count--;
break;
}
}
}
printf("%d", count);
return 0;
}
