题解 | #守形数#

#include <cstdio>
using namespace std;
int main(){
    int n,npow;
    while (scanf("%d",&n)!=EOF){
        npow=n*n;
        if(npow%10==n){
            printf("Yes!\n");
        } else if(npow%100==n){
            printf("Yes!\n");
        } else if(npow%1000==n){
            printf("Yes!\n");
        }else if(npow%10000==n){
            printf("Yes!\n");
        } else{
            printf("No!\n");
        }

    }
}