题解 | #反序数#

#include <iostream>
#include <cstdio>

using namespace std;

int Reverse(int i){
    int reverse=0;
    while (i>0){
        reverse=reverse*10+i%10;
        i=i/10;
    }
    return reverse;
}

int main(){
    for(int i=1000;i<10000;i++){
        if(i*9==Reverse(i)){
            printf("%d\n",i);
        }
    }
    return 0;
}