题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
import sys
while 1:
try:
n = int(input())
l = input().split(' ') #把输入转为链表
k = int(input())
print(l[-k]) #倒数第k个
except:
break
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