题解 | #名字的漂亮度#

import sys
import collections

n = int(input())

for i in range(n):
    s = input()
    c = collections.Counter(s)  # 统计每个字符存在的次数
    #print(c)

    result = 0
    m = 26
    item = sorted(c.items(), key = lambda x:x[1], reverse=True)     #对dict里的value进行排倒序
    for i in item:
        result += i[1] * m
        m -= 1
    print(result)