题解 | #获得积分最多的人(二)#
获得积分最多的人(二)
https://www.nowcoder.com/practice/b6248d075d2d4213948b2e768080dc92
select t1.user_id, name, sum_g grade_num
from (
select user_id, sum(grade_num) sum_g, max(sum(grade_num))over() max_sum_g
from grade_info
where type = 'add'
group by user_id, type
) t1
join user u
on t1.user_id = u.id
where sum_g = max_sum_g
order by user_id;
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