题解 | #变种水仙花#

#include <stdio.h>

int main()
{
    int r = 0, k = 0,i = 0, a = 10, p = 0,sum = 0;
    //外循环控制100~10000
    for(i = 10000; i < 100000; i++ )
    {
        k = i;
        a = 10;
        sum = 0;
      //内循环找出Lily Number
      while(a < i)
      {
        r = i % a;
        k = i / a;
        //把余数和商相乘，且每次的和都要保留
        p = k * r;
        sum = sum + p;
        //执行一次循环，就把除数*10，但被除数不变，依然是所判断的数
        a = a * 10;
      }
      if(sum == i)
      printf("%d ",i);
    }
  return 0;
}