题解 | #今天的刷题量(一)#
今天的刷题量(一)
https://www.nowcoder.com/practice/e18f56796ae94c3d885e61c8d57a950e
select name,count(subject_id) as cnt from submission as t1 inner join subject as t2 on t1.subject_id=t2.id where create_time = curdate() group by name order by cnt desc;

