题解 | #最高分与最低分之差#
最高分与最低分之差
https://www.nowcoder.com/practice/e0e4f81dcd55408a8973f8033bbeb1d2
#include <stdio.h> int main() { int n = 0,max,min; scanf("%d", &n); int arr[n], sum = 0; for (int i = 0; i < n; i++) { scanf("%d ", &arr[i]); } max = min =arr[0]; for (int j =0; j<n; j++) { max = max>arr[j]?max:arr[j]; min = min<arr[j]?min:arr[j]; } printf("%d",max-min); return 0; }