题解 | #合并k个已排序的链表#
合并k个已排序的链表
https://www.nowcoder.com/practice/65cfde9e5b9b4cf2b6bafa5f3ef33fa6
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param lists ListNode类一维数组
# @return ListNode类
#
class Solution:
def mergeKLists(self, lists: List[ListNode]) -> ListNode:
# initiate the aux list
tmp = []
for head in lists:
while head:
tmp.append(head.val)
head = head.next
tmp.sort()
# initiate the result listnode
res = ListNode(0)
cur = res
for val in tmp:
cur.next = ListNode(val)
cur = cur.next
return res.next
