题解 | #合并两个排序的链表#

import java.util.*;

/*
 * public class ListNode {
 *   int val;
 *   ListNode next = null;
 *   public ListNode(int val) {
 *     this.val = val;
 *   }
 * }
 */

public class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 
     * @param pHead1 ListNode类 
     * @param pHead2 ListNode类 
     * @return ListNode类
     */
    public ListNode Merge (ListNode pHead1, ListNode pHead2) {
        // write code here
        ListNode resultHead = new ListNode(0);
        ListNode currentNode = resultHead;
        while(pHead1 != null || pHead2 != null){
            if(pHead1 == null || (pHead2 != null && pHead2.val < pHead1.val)){
                currentNode.next = new ListNode(pHead2.val);
                pHead2 = pHead2.next;
            }
            else{
                currentNode.next = new ListNode(pHead1.val);
                pHead1 = pHead1.next;
            }
            currentNode = currentNode.next;
        }
        currentNode.next = null;
        return resultHead.next;
    }
}