题解 | #牛牛学数列#
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int n=0,i=0,j=0;
scanf("%d",&n);
i=n/2;
j=n%2;
if(j==0)
{
printf("%d\n",-i);
}
else {
printf("%d\n",n-i);
}
return 0;
}
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