题解 | #树的子结构#
树的子结构
https://www.nowcoder.com/practice/6e196c44c7004d15b1610b9afca8bd88
package main
import . "nc_tools"
/*
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
* @param pRoot1 TreeNode类
* @param pRoot2 TreeNode类
* @return bool布尔型
*/
func HasSubtree( pRoot1 *TreeNode , pRoot2 *TreeNode ) bool {
// write code here
if pRoot1 == nil || pRoot2 == nil {
return false
}
if pRoot1.Val == pRoot2.Val {
leftFlag, rightFlag := true, true
if pRoot2.Left != nil {
leftFlag = HasSubtree(pRoot1.Left, pRoot2.Left)
}
if pRoot2.Right != nil {
rightFlag = HasSubtree(pRoot1.Right, pRoot2.Right)
}
if leftFlag && rightFlag {
return true
}
}
return HasSubtree(pRoot1.Left, pRoot2) || HasSubtree(pRoot1.Right, pRoot2)
}