题解 | #获得积分最多的人(二)#
获得积分最多的人(二)
https://www.nowcoder.com/practice/b6248d075d2d4213948b2e768080dc92
select distinct(id), name, grade_num from ( select id, name, grade_num, max(grade_num) over() as max_num from ( select id, name, sum(grade_num) over(partition by user_id order by user_id) as grade_num from user u, grade_info g where u.id = g.user_id ) a ) b where b.grade_num = b.max_num