题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
char=input()
lists=char.split(" ")[1:]
start=lists[0]
end=lists[-1]
del lists[0]
del lists[-1]
new_lists=[]
for i in range(len(lists)):
if i%2==0:
if i==0:
new_lists.append(lists[1])
new_lists.append(lists[0])
else:
new_lists.insert(new_lists.index(lists[i+1])+1,lists[i])
else:
pass
new_lists.remove(end)
for i in new_lists:
print(i,end=" ")
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