题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
char=input() lists=char.split(" ")[1:] start=lists[0] end=lists[-1] del lists[0] del lists[-1] new_lists=[] for i in range(len(lists)): if i%2==0: if i==0: new_lists.append(lists[1]) new_lists.append(lists[0]) else: new_lists.insert(new_lists.index(lists[i+1])+1,lists[i]) else: pass new_lists.remove(end) for i in new_lists: print(i,end=" ")