题解 | #井字棋#

#include <stdio.h>
int main()
{
    char zu[3][3] = { 0 };
    int i1, i2, i3;
    int t = 0;
    for (i1 = 0; i1 < 3; i1++)
    {
        for (i2 = 0; i2 < 3; i2++)
        {
            scanf("%c", &zu[i1][i2]);
            getchar();
        }
    }

    for (i1 = 0; i1 < 3; i1++)//横向判断
    {
         t = 0;
        t = zu[i1][0] + zu[i1][1] + zu[i1][2];
      
        if(t%'K'==0)
        {
            printf("KiKi wins!");
            goto jie;
        }
        if (t % 'B' == 0)
        {
            printf("BoBo wins!");
            goto jie;
        }        
    }

    for (i1 = 0; i1 < 3; i1++)//竖向判断
    {
         t = 0;
        t = zu[0][i1] + zu[1][i1] + zu[2][i1];
        if (t % 'K' == 0)
        {
            printf("KiKi wins!");
            goto jie;
        }
        if (t % 'B' == 0)
        {
            printf("BoBo wins!");
            goto jie;
        }
    }

    t = 0;
    t = zu[0][0] + zu[1][1] + zu[2][2];

    if (t % 'K' == 0)
    {
        printf("KiKi wins!");
        goto jie;
    }
    if(t % 'B' == 0)
    {
        printf("BoBo wins!");
        goto jie;
    }

    t = 0;
    t = zu[2][0] + zu[1][1] + zu[0][2];
    if (t % 'K' == 0)
    {
        printf("KiKi wins!");
        goto jie;
    }
    if (t % 'B' == 0)
    {
        printf("BoBo wins!");
        goto jie;
    }

    printf("No winner!");
    jie:
    return 0;
}