题解 | #记负均正#

#include <stdio.h>

int main() {
    int n;
    scanf("%d",&n);
    int count1=0,count2=0,sum=0,t;
    for(int i=0;i<n;i++){
        scanf("%d",&t);
        if(t<0){
            count1++;
        }
        else if(t>0){
            sum+=t;
        }
        else{
            count2++;
        }
    }
    if(n-count1-count2==0){
        printf("%d 0.0",count1);
    }
    else{
        printf("%d %.1f",count1,sum*1.0/(n-count1-count2));
    }
    return 0;
}