题解 | #包含数字9的数#

int main() {
    int i = 0;
    int count = 0;
    for (i = 1; i <= 2019; i++) {
        int j = 0;
        int m = i;
        while (m) {
            j = m % 10;
            m /= 10;
            if (j == 9) {
                count++;
                break;

            }

        }
    }
    printf("%d", count);
    return 0;
}