题解 | #记负均正II#

#include <iomanip>
#include <iostream>
using namespace std;

int main() {
    int a;
    int cnt = 0;
    int zhengshu_cnt = 0;
    double sum = 0;
    while (cin >> a)
    {
        if (a < 0)
        {
            cnt += 1;
        }
        else if (a > 0)
        {
            sum += a;
            zhengshu_cnt += 1;
        }
    }
    if (zhengshu_cnt == 0)
    {
        cout << cnt << endl << fixed << setprecision(1) << 0.0 << endl;
    }
    else 
    {
        cout << cnt << endl << fixed << setprecision(1) << (sum / zhengshu_cnt) << endl;
    }
}
// 64 位输出请用 printf("%lld")