题解 | #编码#
编码
https://www.nowcoder.com/practice/6fc8716ee33e4cc59d58d7e18712094e
#include <stdio.h>
#include <string.h>
int main() {
char s[100];
scanf("%s", s);
int n = strlen(s);
int v[4] = {
1 + 25 + 25 * 25 + 25 * 25 * 25,
1 + 25 + 25 * 25,
1 + 25,
1
};
int idx = 0;
for (int i = 0; i < n; ++i) {
idx += (s[i] - 'a') * v[i];
}
idx += n - 1;
printf("%d\n", idx);
return 0;
}
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