题解 | #输出单向链表中倒数第k个结点#

import sys

def do(l_num, k):
    return l_num[-k]



if __name__ == '__main__':
    l_lines = sys.stdin.readlines()
    for index in range(len(l_lines)): 
        if index % 3 == 1:
            l_num = [int(i) for i in l_lines[index].strip().split(' ')]
            k = int(l_lines[index+1].strip())
            r = do(l_num, k)
            print(r)