题解 | #统计字符#

text = list(input())

d={'str':0,'space':0,'num':0,'other':0}

for i in text:
    if i.isalpha():
        d['str']+=1
    elif i==' ':
        d['space']+=1
    elif i.isdigit():
        d['num']+=1
    else:
        d['other']+=1

for i,count in d.items():
    print(count)

説的對，就是硬遍历