题解 | #左旋转字符串#
左旋转字符串
https://www.nowcoder.com/practice/12d959b108cb42b1ab72cef4d36af5ec
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param str string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def LeftRotateString(self, ss: str, n: int) -> str:
# write code here
if not ss or n == 0:
return ss
while n > 0:
temp = ss[0]
ss = ss[1:] + temp
n -= 1
return ss
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