题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
# 方法一
# my_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
# n = int(input())
# new_list = []
# for i in my_list:
# j = [i*n for i in i]
# new_list.append(j)
# print(new_list)
# 方法二
my_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
n = int(input())
for i in my_list:
for j in range(len(i)):
i[j] = i[j] * n
print(my_list)
