题解 | #复制部分字符串#
复制部分字符串
https://www.nowcoder.com/practice/8f5b923683b94e549880e3c8370e3e55
//#include <iostream> #include <bits/stdc++.h> #include <stdio.h> #include <string.h> using namespace std; int main() { char str[31] = { 0 }; int m; cin >> str; //gets(str);//c++环境下,这个不能用 int size_old = strlen(str) + 1; scanf("%d\n", &m); int size_new = size_old - (m - 1); /*初始化数组,使其每个元素都是'\0','\0'字符的ascii码就是0:https://blog.csdn.net/qq_32634545/article/details/75454017*/ char str_new[31] = {0};//后面打印用到printf字符串,所以先把每个元素初始化位\0,否则最后一个printf的字符容易出现乱码 /*用指针来实现*/ char *str_ptr = str + m -1; char *str_new_ptr = str_new; while( *str_ptr != '\0'){ *str_new_ptr = *str_ptr; str_new_ptr++; str_ptr++; } /*用数组来实现*/ // for(int i = 0; i < size_new; i++){ // str_new[i] = str[i + m - 1]; // } printf("%s", str_new); return 0; }