题解 | #最长公共前缀#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param strs string字符串一维数组 
# @return string字符串
#
class Solution:
    def longestCommonPrefix(self , strs: List[str]) -> str:
        # write code here
        if len(strs) == 0:
            return ""
        else:
            commonPrex = strs[0]
            for i in range(1,len(strs)):
                if commonPrex == strs[i]:
                    continue
                else:
                    changePrex = ""
                    for j in range(0,min(len(commonPrex),len(strs[i]))):
                        if strs[i][j] == commonPrex[j]:
                            changePrex = changePrex + commonPrex[j]
                        else:
                            break
                    commonPrex = changePrex
            return commonPrex