题解 | #返回每个顾客不同订单的总金额#
返回每个顾客不同订单的总金额
https://www.nowcoder.com/practice/ce313253a81c4947b20e801cd4da7894
select distinct cust_id,sum_pay from (select order_num,sum(item_price*quantity)over (partition by order_num) as sum_pay from OrderItems) a right join Orders o on a.order_num = o.order_num order by sum_pay desc


