题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int n=0; while(scanf("%d",&n)!=EOF)//对整型的多组输入 { printf("%d\n",1<<n);//2的n次方计算 2的几次方就<<动多少 } return 0; }
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int n=0; while(scanf("%d",&n)!=EOF)//对整型的多组输入 { printf("%d\n",1<<n);//2的n次方计算 2的几次方就<<动多少 } return 0; }
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