题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main() {
int seconds,a, b,c;
scanf("%d\n",& seconds);
if( seconds>0 && seconds<100000000)
{
a= seconds/60/60;
b= seconds/60-(a*60);
c= seconds-a*60*60-b*60;
printf("%d %d %d",a,b,c);
}
return 0;
}
投递腾讯等公司10个岗位 >