题解 | #占空比50%的奇数分频#
占空比50%的奇数分频
https://www.nowcoder.com/practice/ccfba5e5785f4b3f9d7ac19ab13d6b31
`timescale 1ns/1ns
module odo_div_or
#(parameter N = 7)
(
input wire rst ,
input wire clk_in,
output wire clk_out7
);
reg [2:0] cnt;
always@(posedge clk_in or negedge rst)begin
if(!rst)
cnt <= 3'd0;
else
cnt <= (cnt == 3'd6) ? 3'd0 : cnt + 1'b1;
end
wire clk_tmp1 = cnt >= 3'd3;
reg clk_tmp2;
always@(negedge clk_in or negedge rst)begin
if(!rst)
clk_tmp2 <= 1'b0;
else
clk_tmp2 <= clk_tmp1;
end
assign clk_out7 = clk_tmp1 & clk_tmp2;
endmodule
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