题解 | #删除有序链表中重复的元素-I#

/**
 * struct ListNode {
 *  int val;
 *  struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 *
 * @param head ListNode类
 * @return ListNode类
 */
struct ListNode* deleteDuplicates(struct ListNode* head ) {
    // write code here
    if (head == NULL || head->next == NULL)
        return head;
    struct ListNode* list_p = head;
    while (list_p->next != NULL) {
        if (list_p->next->val == list_p->val)
            list_p->next = list_p->next->next;
        else
            list_p = list_p->next;
    }
    return head;
}