题解 | #连续两次作答试卷的最大时间窗#
连续两次作答试卷的最大时间窗
https://www.nowcoder.com/practice/9dcc0eebb8394e79ada1d4d4e979d73c
select
uid,
max(DATEDIFF(next_time,start_time))+1 as days_window, #最大时间窗days_window
round(count(start_time)/(DATEDIFF(max(start_time),min(start_time))+1)#连续两次作答最大时间窗
*(max(DATEDIFF(next_time,start_time)) +1)##最大时间窗days_window
,2) as avg_exam_cnt
from (
select
uid,
start_time,
lead(start_time,1) over(partition by uid order by start_time) as next_time
from exam_record
where year(start_time) = '2021'
)t1
group by uid
having count(distinct date(start_time)) > 1
order by days_window desc,avg_exam_cnt desc
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