题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list1 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] n = int(input()) for i, sublist in enumerate(list1): for j, value in enumerate(sublist): list1[i][j] = value * n print(list1)