题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list1 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
n = int(input())
for i, sublist in enumerate(list1):
for j, value in enumerate(sublist):
list1[i][j] = value * n
print(list1)
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