题解 | #删除字符串中出现次数最少的字符#

package main

import (
	"fmt"
)

func main() {
	var s string
	fmt.Scan(&s)

	// 统计字符出现的次数
	counts := make(map[byte]int)
	for i := 0; i < len(s); i++ {
		counts[s[i]]++
	}
	// 找出出现次数最少的字符
	minCount := len(s)
	for _, count := range counts {
		if count < minCount {
			minCount = count
		}
	}
	// 删除出现次数最少的字符
	result := ""
	for i := 0; i < len(s); i++ {
		if counts[s[i]] != minCount {
			result += string(s[i])
		}
	}
	fmt.Println(result)
}

package main

import ( "fmt" )

func main() { 
  var s string 
  fmt.Scan(&s)

// 统计字符出现的次数
counts := make(map[byte]int)
for i := 0; i < len(s); i++ {
    counts[s[i]]++
}

// 找出出现次数最少的字符
minCount := len(s)
for _, count := range counts {
    if count < minCount {
        minCount = count
    }
}

// 删除出现次数最少的字符
result := ""
for i := 0; i < len(s); i++ {
    if counts[s[i]] != minCount {
        result += string(s[i])
    }
}

fmt.Println(result)
}