题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
/** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @param numsLen int nums数组长度 * @param target int整型 * @return int整型 */ int search(int* nums, int numsLen, int target ) { // write code here int low=0; int high = numsLen-1; int middle = (low+high)/2; while(low<=high){ if(nums[middle]==target){ return middle; }else if(nums[middle] < target) { low = middle+1; middle = (low+high)/2; }else { high = middle-1; middle = (low+high)/2; } } return -1; }