题解 | #合并二叉树#
合并二叉树
https://www.nowcoder.com/practice/7298353c24cc42e3bd5f0e0bd3d1d759
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param t1 TreeNode类
* @param t2 TreeNode类
* @return TreeNode类
*/
public TreeNode mergeTrees (TreeNode t1, TreeNode t2) {
// write code here
// 解题思路:需要对2个树的对应节点相加,所以需要遍历树
// 这里采用前序遍历
if (t1 == null) {
return t2;
}
if (t2 == null) {
return t1;
}
TreeNode node = new TreeNode(t1.val + t2.val);
node.left = mergeTrees(t1.left, t2.left);
node.right = mergeTrees(t1.right, t2.right);
return node;
}
}
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