题解 | #有效括号序列#

import java.util.*;


public class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     * @param s string字符串 
     * @return bool布尔型
     */
    public boolean isValid (String s) {
	   //map存储对应关系映射
        HashMap<Character,Character> map =new HashMap(){{
            put('{','}');
            put('(',')');
            put('[',']');
        }};
        Stack<Character> stack = new Stack<>();
        int index= 0;
        while(index<s.length()){//遍历s
            char temp = s.charAt(index);
		  	//当前char与栈顶匹配则出栈
            if(!stack.isEmpty() &&  map.containsKey(stack.peek()) && temp==map.get(stack.peek() )){
                System.out.println("1");
                stack.pop();
            }else{//不匹配则入栈
                stack.push(temp);
                System.out.println("2");
            }
            index++;
        }
        return  stack.isEmpty();//全部配对成功 则最终为空栈
    }
}