题解 | #识别有效的IP地址和掩码并进行分类统计#
识别有效的IP地址和掩码并进行分类统计
https://www.nowcoder.com/practice/de538edd6f7e4bc3a5689723a7435682
#include<iostream>
#include<string>
#include<sstream>
#include<vector>
using namespace std;
bool judge_ip(string ip){
int j = 0;
istringstream iss(ip);
string seg;
while(getline(iss,seg,'.'))
if(++j > 4 || seg.empty() || stoi(seg) > 255)
return false;
return j == 4;
}
bool is_private(string ip){
istringstream iss(ip);
string seg;
vector<int> v;
while(getline(iss,seg,'.')) v.push_back(stoi(seg));
if(v[0] == 10) return true;
if(v[0] == 172 && (v[1] >= 16 && v[1] <= 31)) return true;
if(v[0] == 192 && v[1] == 168) return true;
return false;
}
bool is_mask(string ip){
istringstream iss(ip);
string seg;
unsigned b = 0;
while(getline(iss,seg,'.')) b = (b << 8) + stoi(seg);
if(!b) return false;
b = ~b + 1;
if(b == 1) return false;
if((b & (b-1)) == 0) return true;
return false;
}
int main(){
string input;
int a = 0,b = 0,c = 0,d = 0,e = 0,err = 0,p = 0;
while(cin >> input){
istringstream is(input);
string add;
vector<string> v;
while(getline(is,add,'~')) v.push_back(add);
int num0 = stoi(v[0].substr(0,v[0].find_first_of('.')));
if(num0 == 0 || num0 == 127)continue;
if(!judge_ip(v[1]) || !is_mask(v[1])) err++;
else{
if(!judge_ip(v[0])) err++;
else{
int first = stoi(v[0].substr(0,v[0].find_first_of('.')));
if(is_private(v[0])) p++;
if(first > 0 && first <127) a++;
else if(first > 127 && first <192) b++;
else if(first > 191 && first <224) c++;
else if(first > 223 && first <240) d++;
else if(first > 239 && first <256) e++;
}
}
}
cout << a << " " << b << " " << c << " " << d << " " << e << " " << err << " " << p << endl;
return 0;
}
// 64 位输出请用 printf("%lld")
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