题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
class Node(object):
def __init__(self, elem):
self.elem = elem
self.next = None
class SingleLinkList(object):
def __init__(self,node=None):
self._head = node
def is_empty(self):
return self._head == None
def length(self):
cur = self._head
count = 0
while cur != None:
count += 1
cur = cur.next
return count
def travel(self):
cur = self._head
while cur != None:
print(cur.elem)
cur = cur.next
def add(self,item):
node = Node(item)
node.next = self._head
self._head = node
def append(self,item):
node = Node(item)
if self.is_empty():
self._head = node
else:
cur = self._head
while cur.next != None:
cur = cur.next
cur.next = node
def insert(self,pos,item):
if pos <= 0:
self.add(item)
if pos > (self.length()-1):
self.append(item)
else:
pre = self._head
count = 0
node = Node(item)
while count <(pos - 1):
count += 1
pre = pre.next
node.next = pre.next
pre.next = node
def remove(self,item):
cur = self._head
pre = None
while cur != None:
if cur.elem == item:
if cur == self._head:
self._head = cur.next
else:
pre.next = cur.next
break
else:
pre = cur
cur = cur.next
def search(self,item):
cur = self._head
while cur != None:
if cur.elem == item:
return True
else:
cur = cur.next
return False
def insert_m_after_n(self,m,n):
cur = self._head
while cur != None:
if cur.elem == n:
if cur.next == None:
self.append(m)
else:
node = Node(m)
node.next = cur.next
cur.next = node
break
else:
cur = cur.next
def zhuanzifuchuan(self):
cur = self._head
sty = ""
while cur != None:
sty = sty + str(cur.elem) + " "
cur = cur.next
return sty
if __name__ == "__main__":
ll = SingleLinkList()
stry = input().split()
n = int(stry[0])
ll.add(int(stry[1]))
for i in range(n-1):
ll.insert_m_after_n(int(stry[i*2+2]),int(stry[i*2+3]))
ll.remove(int(stry[-1]))
print(ll.zhuanzifuchuan())

