题解 | #购物单#
购物单
https://www.nowcoder.com/practice/f9c6f980eeec43ef85be20755ddbeaf4
import Foundation
var i = 0
var N = 0
var m = 0
var masterArr = [(sn:Int, price:Int, manyi:Int)]()
var dict = [Int : [(price:Int, manyi:Int)]]()
while let line = readLine() {
let parts = line.split(separator: " ")
if (parts[0] == "***") {
break
}
if (i == 0) {
N = Int(parts[0])!
m = Int(parts[1])!
} else if (Int(parts[2])! == 0) { // 主件
masterArr.append((sn:i - 1, price:Int(parts[0])!, manyi:Int(parts[1])!))
} else {
var fujian:[(price:Int, manyi:Int)] = dict[Int(parts[2])! - 1] ?? []
fujian.append((price:Int(parts[0])!, manyi:Int(parts[1])!))
dict[Int(parts[2])! - 1] = fujian
}
i = i + 1
}
//print(N)
//print(m)
//print(masterArr)
//print(dict)
var amount = masterArr.count
var total = N
var dp:[[Int]] = [[Int]](repeating: [Int](repeating: 0, count: total + 1), count: amount + 1)
func calulate(total:Int, amount:Int) {
// i 前i个,total:最大的钱数[0, tatal], dp:最大的满意度
for i in 0 ... amount {
for j in 0 ... total {
if ( i == 0) {
dp[0][j] = 0
continue
}
if (j == 0) {
dp[i][0] = 0
continue
}
var maxVal = 0
// 是否选择第i个 选择,不选择
// 不选择
dp[i][j] = dp[i - 1][j]
maxVal = max(dp[i][j], maxVal)
// 选择主件和附件,前i个,对应的下标就是 i - 1
var master = masterArr[i - 1]
var fujians = dict[master.sn] ?? []
// 选择 有多种情况
// 只选主件、 选主件和附件1、选主件和附件2、选主件和附件1和2
if j - master.price >= 0 {
dp[i][j] = dp[i - 1][j - master.price] + master.price * master.manyi
maxVal = max(dp[i][j], maxVal)
}
if fujians.count == 1 {
// 主件 + 附件1
var fujian1 = fujians[0]
if (j - master.price - fujian1.price >= 0) {
dp[i][j] = dp[i - 1][j - master.price - fujian1.price] + master.price * master.manyi + fujian1.price * fujian1.manyi
maxVal = max(dp[i][j], maxVal)
}
} else if fujians.count == 2 {
var fujian1 = fujians[0]
var fujian2 = fujians[1]
// 主件 + 附件1
if (j - master.price - fujian1.price >= 0) {
dp[i][j] = dp[i - 1][j - master.price - fujian1.price] + master.price * master.manyi + fujian1.price * fujian1.manyi
maxVal = max(dp[i][j], maxVal)
}
// 主件 + 附件2
if (j - master.price - fujian2.price >= 0) {
dp[i][j] = dp[i - 1][j - master.price - fujian2.price] + master.price * master.manyi + fujian2.price * fujian2.manyi
maxVal = max(dp[i][j], maxVal)
}
// 主件 + 附件1 + 附件2
if (j - master.price - fujian1.price - fujian2.price >= 0) {
dp[i][j] = dp[i - 1][j - master.price - fujian1.price - fujian2.price] + master.price * master.manyi + fujian1.price * fujian1.manyi + fujian2.price * fujian2.manyi
maxVal = max(dp[i][j], maxVal)
}
}
dp[i][j] = maxVal
}
}
}
calulate(total: total, amount: amount)
print(dp[amount][total])
#华为OD的机试题目不容易啊#