题解 | #获取每个部门中当前员工薪水最高的相关信息#

select dept_no
,emp_no
,round(avg(maxSalary),0) maxSalary
from
(
  select dept_no
  ,first_value(dept_emp.emp_no)over(partition by dept_no order by salary desc) emp_no
  ,max(salary)over(partition by dept_no) maxSalary
  from dept_emp left join salaries on dept_emp.emp_no = salaries.emp_no
) a
group by 1,2
order by 1